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我现在对于3个变量LNHP,LNLP和LNDL做了unit root test。他们的图形显示是有趋势上升,但当我选择ADFtest的trend+intercept的时候,得到两个变量level stationary,一个变量一阶平稳。如果是不加trend的话就3个变量都是I(1)。理论应该是3个变量应该同阶平稳才能做协整,那是否就是说Johansen co-integration 方程也只能用不加trend的方程来做?
这个是只有intercept的Johansen结论
Date: 03/21/11 Time: 21:58
Sample (adjusted): 2000Q1 2010Q3
Included observations: 43 after adjustments
Trend assumption: Linear deterministic trend
Series: LNHP LNLP LNDL
Lags interval (in first differences): 1 to 3
Unrestricted Cointegration Rank Test (Trace)
Hypothesized
Trace
0.05
No. of CE(s)
Eigenvalue
Statistic
Critical Value
Prob.**
None *
0.593747
42.07473
29.79707
0.0012
At most 1
0.074345
3.341269
15.49471
0.9493
At most 2
0.000450
0.019373
3.841466
0.8892
Trace test indicates 1 cointegrating eqn(s) at the 0.05 level
* denotes rejection of the hypothesis at the 0.05 level
**MacKinnon-Haug-Michelis (1999) p-values
Unrestricted Cointegration Rank Test (Maximum Eigenvalue)
Hypothesized
Max-Eigen
0.05
No. of CE(s)
Eigenvalue
Statistic
Critical Value
Prob.**
None *
0.593747
38.73346
21.13162
0.0001
At most 1
0.074345
3.321896
14.26460
0.9230
At most 2
0.000450
0.019373
3.841466
0.8892
Max-eigenvalue test indicates 1 cointegrating eqn(s) at the 0.05 level
* denotes rejection of the hypothesis at the 0.05 level
**MacKinnon-Haug-Michelis (1999) p-values
Unrestricted Cointegrating Coefficients (normalized by b'*S11*b=I):
LNHP
LNLP
LNDL
-27.16853
4.524538
6.748176
24.02210
-3.217646
-4.067153
-68.06757
64.78095
-4.132913
Unrestricted Adjustment Coefficients (alpha):
D(LNHP)
0.012561
-0.002259
0.000120
D(LNLP)
0.030357
0.001779
4.97E-05
D(LNDL)
0.015009
0.011993
0.002560
1 Cointegrating Equation(s):
Log likelihood
254.8786
Normalized cointegrating coefficients (standard error in parentheses)
LNHP
LNLP
LNDL
1.000000
-0.166536
-0.248382
(0.13776)
(0.04789)
Adjustment coefficients (standard error in parentheses)
D(LNHP)
-0.341270
(0.06939)
D(LNLP)
-0.824762
(0.12511)
D(LNDL)
-0.407768
(0.61947)
2 Cointegrating Equation(s):
Log likelihood
256.5396
Normalized cointegrating coefficients (standard error in parentheses)
LNHP
LNLP
LNDL
1.000000
0.000000
0.155676
(0.21844)
0.000000
1.000000
2.426248
(1.32134)
Adjustment coefficients (standard error in parentheses)
D(LNHP)
-0.395540
0.064103
(0.09149)
(0.01401)
D(LNLP)
-0.782037
0.131630
(0.16661)
(0.02551)
D(LNDL)
-0.119664
0.029318
(0.82331)
(0.12604)
(这里还想请问一下如果要写Johansen给出的方程,系数的t-value要在哪里看?)
谢谢!!!