行列转换简单示例Before转换
| Obs | TRTN | AGEGR1N | AVAL | 
| 1 | 1 | 1 | 11 | 
| 2 | 1 | 2 | 12 | 
| 3 | 1 | 3 | 13 | 
| 4 | 2 | 1 | 21 | 
| 5 | 2 | 2 | 22 | 
| 6 | 2 | 3 | 23 | 
After转换| Obs | TRTN | AGEGR_1 | AGEGR_2 | AGEGR_3 | 
| 1 | 1 | 11 | 12 | 13 | 
| 2 | 2 | 21 | 22 | 23 | 
>首选方案proc transpose一发入魂?\
code示例如下
data test;
TRTN=1; AGEGR1N=1; AVAL=11; output;
TRTN=1; AGEGR1N=2; AVAL=12; output;
TRTN=1; AGEGR1N=3; AVAL=13; output;
TRTN=2; AGEGR1N=1; AVAL=21; output;
TRTN=2; AGEGR1N=2; AVAL=22; output;
TRTN=2; AGEGR1N=3; AVAL=23; output;
run;
proc transpose data=test out=test_tran0 prefix=AGEGR_; 
  by TRTN;
  id AGEGR1N;
  var AVAL;
run;
>替代方案1利用data过程步的retain+if first/if last组合
data test_tran1;
  set test;
  by TRTN AGEGR1N;
  retain AGEGR_1 AGEGR_2 AGEGR_3;
  if first.TRTN then call missing(AGEGR_1,AGEGR_2,AGEGR_3);
  if AGEGR1N=1 then AGEGR_1=AVAL;
  if AGEGR1N=2 then AGEGR_2=AVAL;
  if AGEGR1N=3 then AGEGR_3=AVAL;
  if last.TRTN then output;
  keep TRTN AGEGR_1 AGEGR_2 AGEGR_3;
run;
>替代方案2讨厌data过程步,特别偏爱sql的小伙伴们可以看看下面示例code,估计很少有人用,我反正是没见过其他sp这个写过,嘿嘿
proc sql noprint;
  create table test_tran2 as
  select distinct TRTN
            , max(case when AGEGR1N=1 then AVAL else . end) as AGEGR_1
            , max(case when AGEGR1N=2 then AVAL else . end) as AGEGR_2
            , max(case when AGEGR1N=3 then AVAL else . end) as AGEGR_3
  from test
  group by TRTN;
quit;
>两种方案的执行结果
 结论
结论码code是个辛苦的体力活,偶尔换个解法,换个思维,枯燥也许会变的有趣,工作也许更有动力。
以上介绍仅供参考,具体问题具体对待,如果有更有趣的解法欢迎留言探讨,共同进步。