scalar是时间，怎么做减法

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收藏 2012-11-05

悬赏 50 个论坛币已解决

写程序计算时间：
sca time1=c(current_time)
。。。。
program
。。。。。
。。。。

sca time2=c(current_time)

scalar list
－－－－－－－－－
结果显示
.    scalar list
   time2 = 02:43:39
   time1 = 02:37:20
－－－－－－－－－－－－－
问题用什么命令算出两者的差异，sca diff=time2-time1好像不对

最佳答案

大白菜2012 查看完整内容

. sca time1=c(current_time) . . forval x=1/10 { 2. qui webuse nlswork,clear 3. } . . sca time2=c(current_time) . . sca h1=real(substr(time1,1,2)) . sca h2=real(substr(time2,1,2)) . sca m1=real(substr(time1,4,2)) . sca m2=real(substr(time2,4,2)) . sca s1=real(substr(time1,7,2)) . sca s2=real(substr(time2,7,2)) . . sca diff=(h2-h1)*60*60+(m2-m1)*60+(s2-s1) // ...

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全部回复

大白菜2012

2012-11-5 02:58:48

. sca time1=c(current_time)

.
. forval x=1/10 {
  2. qui webuse nlswork,clear
  3. }

.
. sca time2=c(current_time)

.
. sca h1=real(substr(time1,1,2))

. sca h2=real(substr(time2,1,2))

. sca m1=real(substr(time1,4,2))

. sca m2=real(substr(time2,4,2))

. sca s1=real(substr(time1,7,2))

. sca s2=real(substr(time2,7,2))

.
. sca diff=(h2-h1)*60*60+(m2-m1)*60+(s2-s1) //unit is second

.
. sca drop h1 h2 m1 m2  s1 s2

. sca list
   diff =       11
   time2 = 15:44:50
   time1 = 15:44:39

.