| x2^2 | x2 | x1 | y |
30.25 | 5.5 | -0.05 | 7.38 |
45.56 | 6.75 | 0.25 | 8.51 |
52.56 | 7.25 | 0.6 | 9.52 |
30.25 | 5.5 | 0 | 7.5 |
49 | 7 | 0.25 | 9.33 |
42.25 | 6.5 | 0.2 | 8.28 |
45.56 | 6.75 | 0.15 | 8.75 |
27.56 | 5.25 | 0.05 | 7.87 |
27.56 | 5.25 | -0.15 | 7.1 |
36 | 6 | 0.15 | 8 |
42.25 | 6.5 | 0.2 | 7.89 |
39.06 | 6.25 | 0.1 | 8.15 |
49 | 7 | 0.4 | 9.1 |
47.61 | 6.9 | 0.45 | 8.86 |
46.24 | 6.8 | 0.35 | 8.9 |
46.24 | 6.8 | 0.3 | 8.87 |
50.41 | 7.1 | 0.5 | 9.26 |
49 | 7 | 0.5 | 9 |
46.24 | 6.8 | 0.4 | 8.75 |
42.25 | 6.5 | -0.05 | 7.95 |
39.06 | 6.25 | -0.05 | 7.65 |
36 | 6 | -0.1 | 7.27 |
42.25 | 6.5 | 0.2 | 8 |
49 | 7 | 0.1 | 8.5 |
46.24 | 6.8 | 0.5 | 8.75 |
46.24 | 6.8 | 0.6 | 9.21 |
42.25 | 6.5 | -0.05 | 8.27 |
33.06 | 5.75 | 0 | 7.67 |
33.64 | 5.8 | 0.05 | 7.93 |
46.24 | 6.8 | 0.55 | 9.26 |
这是数据，我用spss求，求出回归曲线。当x1=0.2,x2=6.5时求95%的置信区间，步骤如下，分析-回归分析-线性-保存-预测区间（均值 单值），求得结果为8.29330，
ResidualsStatistics(a)| | Minimum | Maximum | Mean | Std. Deviation | N |
Predicted Value | 7.3351 | 9.6395 | 8.3827 | .64822 | 30 |
Std. Predicted Value | -1.616 | 1.939 | .000 | 1.000 | 30 |
Standard Error of Predicted Value | .048 | .131 | .078 | .023 | 30 |
Adjusted Predicted Value | 7.4573 | 9.6855 | 8.3827 | .64996 | 30 |
Residual | -.40330 | .46602 | .00000 | .20954 | 30 |
Std. Residual | -1.822 | 2.106 | .000 | .947 | 30 |
Stud. Residual | -1.889 | 2.273 | .000 | 1.025 | 30 |
Deleted Residual | -.43320 | .54298 | .00000 | .24730 | 30 |
Stud. Deleted Residual | -1.994 | 2.490 | .006 | 1.057 | 30 |
Mahal. Distance | .392 | 9.225 | 2.900 | 2.373 | 30 |
Cook's Distance | .000 | .293 | .048 | .074 | 30 |
Centered Leverage Value | .014 | .318 | .100 | .082 | 30 |
预测区间是（
7.3351，9.6395）吗？可是给出的答案是预测值为8.2928，预测区间是（7.8230,8.7636）差的挺多的，不知道是哪里算错了，还是说方法不对，求指导！
扫码加好友，拉您进群
全部版块
我的主页
收藏
