[求助]请高手帮我分析一下Stata估计结果

imycy

2522

收藏 2008-03-13

xtlogit dpen othc L_capc L_crdi L_gdpg L_cgdp L_mrev L_intr [iweight=w1/1000],noconstant

Random-effects logistic regression Number of obs = 375
Group variable (i): contry Number of groups = 15

Random effects u_i ~ Gaussian                   Obs per group: min =        25
                                                               avg =      25.0
                                                               max =        25

Wald chi2(7) = 104.70
Log likelihood = -698.53198 Prob > chi2 = 0.0000

------------------------------------------------------------------------------
        dpen |      Coef.   Std. Err.      z    P>|z|     [95% Conf. Interval]
-------------+----------------------------------------------------------------
        othc |   .1814684   .1057895     1.72   0.086    -.0258753     .388812
      L_capc | -1.700963   .2696962    -6.31   0.000    -2.229558   -1.172368
      L_crdi | -1.87e-06   6.92e-07    -2.70   0.007    -3.22e-06   -5.12e-07
      L_gdpg |   .0001793   .0000716     2.51   0.012      .000039    .0003195
      L_cgdp | -.0410735   .0267343    -1.54   0.124    -.0934718    .0113247
      L_mrev |   .1223328   .0379114     3.23   0.001     .0480279    .1966378
      L_intr | -.0588454   .0139878    -4.21   0.000    -.0862609   -.0314299
-------------+----------------------------------------------------------------
    /lnsig2u | -4.827636   .5021998                      -5.81193   -3.843343
-------------+----------------------------------------------------------------
     sigma_u |    .089473   .0224667                       .054696    .1463621
         rho |   .0024274   .0012161                      .0009085    .0064693
------------------------------------------------------------------------------
Likelihood-ratio test of rho=0: chibar2(01) =     1.75 Prob >= chibar2 = 0.093

上述估计结果中的最后一行“Likelihood-ratio test of rho=0: chibar2(01) = 1.75 Prob >= chibar2 = 0.093”是检验什么的？先谢谢了！