<p><span style="; FONT-FAMILY: 宋体; mso-bidi-font-family: "Times New Roman"; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA;">因变量的值固定在一个0-1的范围，而解释变量的值是不固定的，有非常大的数值，也有非常小的数值，并且解释变量有五个，y=a+a1*X1+a2*X2+a3*X3+a4*x4+a5*X5.时间是从2003-2006年，<span style="; FONT-FAMILY: 宋体; mso-bidi-font-family: "Times New Roman"; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA;">用非线性评定模型来估计，<span style="; FONT-FAMILY: 宋体; mso-bidi-font-family: "Times New Roman"; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA;">用二阶段最小二乘估计方法来克服其中解释变量间的内生性，同时运用<span style="; FONT-FAMILY: 宋体; mso-bidi-font-family: "Times New Roman"; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA;">双截距</span><span style="; FONT-FAMILY: 宋体; mso-bidi-font-family: "Times New Roman"; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: "Times New Roman"; mso-hansi-font-family: "Times New Roman";">（</span><span lang="EN-US" style="; FONT-FAMILY: "Times New Roman"; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋体;">Double-truncated</span><span style="; FONT-FAMILY: 宋体; mso-bidi-font-family: "Times New Roman"; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: "Times New Roman"; mso-hansi-font-family: "Times New Roman";">）</span><span lang="EN-US" style="; FONT-FAMILY: "Times New Roman"; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋体;">Tobit</span><span style="; FONT-FAMILY: 宋体; mso-bidi-font-family: "Times New Roman"; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA;">模型使得因变量的数值保持在0-1的范围内，我想问的是这样具体该怎么操作，用Eviews怎么操作呢？</span></span></span></span></p>