Estimation Command:
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LS LOG(Y) C LOG(X) AR(1) AR(2)

Estimation Equation:
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LOG(Y) = C(1) + C(2)*LOG(X) + [AR(1)=C(3),AR(2)=C(4)]

Substituted Coefficients:
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LOG(Y) = 1.46241331343 + 0.865725163405*LOG(X) + [AR(1)=1.15310014214,AR(2)=-0.516671983085]
这是EVIEWS广义差分运行结果，请问最后一个方程的完全展开式应该是什么？或者AR(1)=1.15310014214中的1.15310014214是什么参数？