from sys import exitdef gold_room():
    print "This room is full of gold. How much do you take."
    next = raw_input("> ")
    if "0" in next or "1" in next:
        how_much = int(next)
    else:
        dead("Man, learn to type a number."

    if how_much < 50:
        print "Nice, You're not greedy. You win!"
       exit(0)
    else:
        dead("You greedy bastard!")



以上是照着书里敲的函数，运行的时候报错

PS C:\Python_TEST> python ex35.py
  File "ex35.py", line 13
    if how_much < 50:
                                ^
SyntaxError: invalid syntax