第一行, visit=1, x=1, 结果为什么不是y ?

if (visit=1 & x=1) |(vist>1 & x in(2 3)) then tag="Y";

每个个体每个指标在visit=1 其x是1 和 visit>1 其x是2或3时

data aaa1;
set aaa;
if visit=1 and x=1 then flag1='Y';
if visit>1 and x in (2,3) then flag2='Y';
run;

proc sql;
create table wanted(drop=flag1 flag2) as
select *, "Y" as tag
from aaa1
group by 1,2
having sum(flag1="Y")>0 and sum(flag2="Y")>0
union
select *, " " as tag
from aaa1
group by 1,2
having not (sum(flag1="Y")>0 and sum(flag2="Y")>0)
order by no, zb, visit;
quit;