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论坛 数据科学与人工智能 数据分析与数据科学 SAS专版
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2009-07-24
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proc format;
value happiness 1='1级' 2='2级' 3='3级' 4='4级' 5='5级';
value marrital_status  0='单身' 1='已婚';
value education 1 ='小学' 2 ='初中' 3 ='高中' 4='大学' 5='硕士及以上';
value saving 0='无储蓄' 1='有储蓄';
value applied 0='未申请' 1='申请过';
value havecard 0='无卡' 1='有卡';

run;
data yy;
missing a ;
input (happiness marrital_status education  saving
applied havecard   )(1.);
if n( of happiness marrital_status education  saving
applied havecard ) eq 0 then do;
  input;
   return;
end;
format happiness happiness.
marrital_status marrital_status.
education  education.  
saving saving.
applied applied.
havecard havecard. ;
      output;
cards;
4 0 6 1 1 1
2 0 5 0 1 1
4 0 5 0 1 0
4 0 6 1 1 1
3 0 6 0 0 0
4 0 3 1 0 0
3 0 5 0 0 0
4 1 5 1 1 1
4 0 5 0 0 0
3 0 6 0 1 1
4 0 6 0 1 1
5 0 4 0 1 1
4 0 6 0 1 1
4 1 6 1 1 1
2 0 5 0 1 1
4 0 6 0 1 1
3 0 5 0 1 1
3 0 5 0 0 0
4 0 5 0 1 1
3 0 5 0 0 0
3 0 5 0 0 0
3 0 6 0 1 1
4 1 5 0 1 1
3 1 6 1 1 1
4 0 6 0 1 1
3 0 6 0 1 1
5 0 6 1 1 1
4 0 4 1 1 1
3 1 5 0 1 1
3 0 6 0 1 1
4 0 5 1 0 0
3 0 5 0 0 0
2 0 5 0 1 0
2 1 6 1 1 1
4 0 6 0 1 0
4 0 5 0 0 1
3 0 6 0 1 1
1 0 5 0 0 0
4 1 6 1 1 1
1 0 5 0 0 0
4 0 6 0 1 1
4 0 5 1 1 0
4 0 6 0 1 1
4 1 5 0 1 1
3 0 6 1 0 0
4 0 6 1 1 1
4 0 5 0 1 1
3 0 5 1 1 1
4 0 3 1 0 0
3 0 5 0 1 1
4 0 6 0 1 1
3 0 5 1 1 1
4 0 6 1 1 1
4 0 5 0 1 1
4 0 5 0 0 0
4 0 6 1 1 1
4 0 5 1 1 1
4 1 6 0 1 1
4 1 6 0 1 1
3 0 4 0 0 0
3 0 5 0 1 0
4 0 5 0 1 1
3 0 5 0 1 1
5 0 6 1 1 1
4 0 6 1 1 1
3 0 5 0 0 0
2 0 1 0 0 0
4 1 5 1 1 1
3 1 6 1 1 1
2 0 5 0 0 0
4 0 6 0 0 0
4 0 6 0 0 0
3 0 5 0 1 1
3 1 5 1 0 0
4 0 6 0 0 0
4 0 5 0 1 1
3 0 5 1 0 0
4 1 6 1 1 1
4 0 5 0 0 0
3 0 5 0 1 1
4 0 5 0 1 0
3 0 5 0 1 1
1 0 6 0 0 0
3 0 6 1 1 1
4 0 6 0 1 1
4 1 6 1 1 1
4 0 6 1 1 1
3 0 5 0 1 1
4 1 5 1 1 1
2 0 5 0 1 1
4 0 5 0 1 1
2 0 1 1 0 1
4 0 6 0 1 1
5 1 6 1 0 0
4 0 6 0 1 1
3 0 5 1 0 0
3 0 5 0 0 0
5 1 6 1 1 1
3 0 6 1 1 1
4 0 5 0 1 1
4 1 6 0 1 0
3 0 1 0 0 0
4 0 5 0 0 0
1 0 4 0 1 1
3 0 6 0 1 1
4 0 6 1 1 1
4 0 6 0 0 0
3 0 5 0 1 1
4 0 6 0 1 0
3 0 5 1 1 1
3 0 6 1 1 1
4 1 5 0 1 1
3 0 5 1 1 1
3 0 5 1 1 1
2 0 5 0 1 0
3 0 5 1 1 1
1 0 5 0 1 1
4 0 5 0 1 1
4 0 6 0 1 0
3 0 5 0 1 1
4 0 5 1 1 1
4 0 6 0 1 0
3 0 6 1 1 1
4 1 5 0 1 1
5 1 6 1 1 1
3 0 4 1 0 0
1 0 6 1 1 1
4 0 5 1 1 1
4 0 6 0 1 0
2 0 6 0 1 1
4 0 5 0 1 1
3 0 5 0 1 0
4 0 5 0 1 1
4 0 5 0 0 0
3 0 5 0 1 1
3 0 5 0 1 0
2 0 6 0 0 0
3 0 5 0 0 0
3 0 6 1 0 0
3 0 5 1 1 1
4 0 5 0 1 1
4 0 5 0 0 0
3 0 5 1 1 1
3 0 5 1 1 1
3 1 6 0 1 1
3 0 5 0 0 0
3 1 5 1 0 0
4 0 5 0 0 0
4 0 6 0 1 1
3 0 6 0 0 0
5 0 5 0 0 1
4 1 5 1 1 1
2 0 5 0 1 1
3 0 5 1 1 1
4 1 5 1 1 1
3 0 5 1 1 0
3 0 5 0 0 0
3 0 5 0 1 1
4 0 5 0 1 1
2 1 5 0 1 1
4 0 5 1 1 1
4 1 5 1 1 1
4 1 5 0 1 1
4 1 6 0 1 1
4 0 6 1 0 0
4 1 6 0 1 1
2 1 6 0 1 1
3 1 6 0 0 0
4 0 6 0 1 1
2 1 5 0 1 1
3 0 6 0 1 1
4 0 5 0 0 0
4 1 6 0 0 0
4 0 6 1 1 1
4 0 6 0 1 1
4 0 5 0 1 1
2 0 6 0 1 1
4 0 6 1 1 1
3 0 5 0 1 1
3 0 5 0 1 1
1 0 6 0 1 1
4 0 6 0 0 0
4 0 5 0 1 1
3 0 5 1 1 1
4 1 1 0 1 1
4 0 6 0 1 1
4 0 6 0 1 0
5 0 6 0 1 1
4 0 5 0 1 0
4 0 5 0 1 1
3 0 5 1 1 0
4 0 6 0 1 1
2 0 6 0 1 1
4 1 5 1 0 1
3 0 6 0 1 1
4 0 5 1 0 0
4 0 5 0 1 1
4 1 6 1 1 1
3 1 6 1 0 0
4 0 5 0 0 0
2 0 5 0 0 0
4 0 3 0 1 1
4 0 6 1 1 1
4 0 5 1 0 0
4 0 5 0 0 0
3 0 5 0 1 1
2 0 5 0 1 1
3 0 5 1 0 0
5 0 5 1 1 1
4 0 6 0 1 1
3 1 5 0 1 1
4 0 5 0 1 1
4 0 5 0 1 1
4 0 6 1 0 0
4 0 6 1 1 1
4 0 5 0 1 1
3 0 6 0 1 1
3 0 6 0 1 1
4 0 6 0 1 1
3 0 5 0 0 0
4 1 6 0 0 0
3 1 6 1 1 1
5 0 5 0 1 1
5 1 6 1 1 1
4 1 5 0 1 1
2 0 5 0 1 1
;
proc corresp mca observed  data=yy outc=coor;
tables  happiness marrital_status education  saving
applied havecard  ;
run;
proc plot data=coor vtoh=2;
plot dim1*dim2='*' $ _name_/
haxis=by 1 vaxis=by 1 box href=0 vref=0;
run;

最佳答案

2433 查看完整内容

*可以了!! proc format; value happiness 1='1级' 2='2级' 3='3级' 4='4级' 5='5级'; value marrital_status 0='单身' 1='已婚'; value education 1 ='小学' 2 ='初中' 3 ='高中' 4='大学' 5='硕士及以上'; value saving 0='无储蓄' 1='有储蓄'; value applied 0='未申请' 1='申请过'; value havecard 0='无卡' 1='有卡'; run; data yy; missing a ; input happiness marrital_status education saving applied ...
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2009-7-24 17:45:36
*可以了!!


proc format;
value happiness 1='1级' 2='2级' 3='3级' 4='4级' 5='5级';
value marrital_status  0='单身' 1='已婚';
value education 1 ='小学' 2 ='初中' 3 ='高中' 4='大学' 5='硕士及以上';
value saving 0='无储蓄' 1='有储蓄';
value applied 0='未申请' 1='申请过';
value havecard 0='无卡' 1='有卡';
run;
data yy;
missing a ;
input happiness marrital_status education  saving applied havecard@@;
/*if n( of happiness marrital_status education  saving
applied havecard ) eq 0 then do;
  input;
   return;
end;*/
format happiness happiness.
marrital_status marrital_status.
education  education.  
saving saving.
applied applied.
havecard havecard. ;
*      output;
cards;
4 0 6 1 1 1
2 0 5 0 1 1
4 0 5 0 1 0
4 0 6 1 1 1
3 0 6 0 0 0
4 0 3 1 0 0
3 0 5 0 0 0
4 1 5 1 1 1
4 0 5 0 0 0
3 0 6 0 1 1
4 0 6 0 1 1
5 0 4 0 1 1
4 0 6 0 1 1
4 1 6 1 1 1
2 0 5 0 1 1
4 0 6 0 1 1
3 0 5 0 1 1
3 0 5 0 0 0
4 0 5 0 1 1
3 0 5 0 0 0
3 0 5 0 0 0
3 0 6 0 1 1
4 1 5 0 1 1
3 1 6 1 1 1
4 0 6 0 1 1
3 0 6 0 1 1
5 0 6 1 1 1
4 0 4 1 1 1
3 1 5 0 1 1
3 0 6 0 1 1
4 0 5 1 0 0
3 0 5 0 0 0
2 0 5 0 1 0
2 1 6 1 1 1
4 0 6 0 1 0
4 0 5 0 0 1
3 0 6 0 1 1
1 0 5 0 0 0
4 1 6 1 1 1
1 0 5 0 0 0
4 0 6 0 1 1
4 0 5 1 1 0
4 0 6 0 1 1
4 1 5 0 1 1
3 0 6 1 0 0
4 0 6 1 1 1
4 0 5 0 1 1
3 0 5 1 1 1
4 0 3 1 0 0
3 0 5 0 1 1
4 0 6 0 1 1
3 0 5 1 1 1
4 0 6 1 1 1
4 0 5 0 1 1
4 0 5 0 0 0
4 0 6 1 1 1
4 0 5 1 1 1
4 1 6 0 1 1
4 1 6 0 1 1
3 0 4 0 0 0
3 0 5 0 1 0
4 0 5 0 1 1
3 0 5 0 1 1
5 0 6 1 1 1
4 0 6 1 1 1
3 0 5 0 0 0
2 0 1 0 0 0
4 1 5 1 1 1
3 1 6 1 1 1
2 0 5 0 0 0
4 0 6 0 0 0
4 0 6 0 0 0
3 0 5 0 1 1
3 1 5 1 0 0
4 0 6 0 0 0
4 0 5 0 1 1
3 0 5 1 0 0
4 1 6 1 1 1
4 0 5 0 0 0
3 0 5 0 1 1
4 0 5 0 1 0
3 0 5 0 1 1
1 0 6 0 0 0
3 0 6 1 1 1
4 0 6 0 1 1
4 1 6 1 1 1
4 0 6 1 1 1
3 0 5 0 1 1
4 1 5 1 1 1
2 0 5 0 1 1
4 0 5 0 1 1
2 0 1 1 0 1
4 0 6 0 1 1
5 1 6 1 0 0
4 0 6 0 1 1
3 0 5 1 0 0
3 0 5 0 0 0
5 1 6 1 1 1
3 0 6 1 1 1
4 0 5 0 1 1
4 1 6 0 1 0
3 0 1 0 0 0
4 0 5 0 0 0
1 0 4 0 1 1
3 0 6 0 1 1
4 0 6 1 1 1
4 0 6 0 0 0
3 0 5 0 1 1
4 0 6 0 1 0
3 0 5 1 1 1
3 0 6 1 1 1
4 1 5 0 1 1
3 0 5 1 1 1
3 0 5 1 1 1
2 0 5 0 1 0
3 0 5 1 1 1
1 0 5 0 1 1
4 0 5 0 1 1
4 0 6 0 1 0
3 0 5 0 1 1
4 0 5 1 1 1
4 0 6 0 1 0
3 0 6 1 1 1
4 1 5 0 1 1
5 1 6 1 1 1
3 0 4 1 0 0
1 0 6 1 1 1
4 0 5 1 1 1
4 0 6 0 1 0
2 0 6 0 1 1
4 0 5 0 1 1
3 0 5 0 1 0
4 0 5 0 1 1
4 0 5 0 0 0
3 0 5 0 1 1
3 0 5 0 1 0
2 0 6 0 0 0
3 0 5 0 0 0
3 0 6 1 0 0
3 0 5 1 1 1
4 0 5 0 1 1
4 0 5 0 0 0
3 0 5 1 1 1
3 0 5 1 1 1
3 1 6 0 1 1
3 0 5 0 0 0
3 1 5 1 0 0
4 0 5 0 0 0
4 0 6 0 1 1
3 0 6 0 0 0
5 0 5 0 0 1
4 1 5 1 1 1
2 0 5 0 1 1
3 0 5 1 1 1
4 1 5 1 1 1
3 0 5 1 1 0
3 0 5 0 0 0
3 0 5 0 1 1
4 0 5 0 1 1
2 1 5 0 1 1
4 0 5 1 1 1
4 1 5 1 1 1
4 1 5 0 1 1
4 1 6 0 1 1
4 0 6 1 0 0
4 1 6 0 1 1
2 1 6 0 1 1
3 1 6 0 0 0
4 0 6 0 1 1
2 1 5 0 1 1
3 0 6 0 1 1
4 0 5 0 0 0
4 1 6 0 0 0
4 0 6 1 1 1
4 0 6 0 1 1
4 0 5 0 1 1
2 0 6 0 1 1
4 0 6 1 1 1
3 0 5 0 1 1
3 0 5 0 1 1
1 0 6 0 1 1
4 0 6 0 0 0
4 0 5 0 1 1
3 0 5 1 1 1
4 1 1 0 1 1
4 0 6 0 1 1
4 0 6 0 1 0
5 0 6 0 1 1
4 0 5 0 1 0
4 0 5 0 1 1
3 0 5 1 1 0
4 0 6 0 1 1
2 0 6 0 1 1
4 1 5 1 0 1
3 0 6 0 1 1
4 0 5 1 0 0
4 0 5 0 1 1
4 1 6 1 1 1
3 1 6 1 0 0
4 0 5 0 0 0
2 0 5 0 0 0
4 0 3 0 1 1
4 0 6 1 1 1
4 0 5 1 0 0
4 0 5 0 0 0
3 0 5 0 1 1
2 0 5 0 1 1
3 0 5 1 0 0
5 0 5 1 1 1
4 0 6 0 1 1
3 1 5 0 1 1
4 0 5 0 1 1
4 0 5 0 1 1
4 0 6 1 0 0
4 0 6 1 1 1
4 0 5 0 1 1
3 0 6 0 1 1
3 0 6 0 1 1
4 0 6 0 1 1
3 0 5 0 0 0
4 1 6 0 0 0
3 1 6 1 1 1
5 0 5 0 1 1
5 1 6 1 1 1
4 1 5 0 1 1
2 0 5 0 1 1
;
proc corresp mca observed  data=yy outc=coor;
tables  happiness marrital_status education  saving
applied havecard  ;
run;
proc plot data=coor vtoh=2;
plot dim1*dim2='*' $ _name_/
haxis=by 1 vaxis=by 1 box href=0 vref=0;
run;
quit;
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2009-7-24 20:52:55
NOTE: Chi-Square statistics and degrees of freedom are only valid when the table of observed frequencies is an ordinary
      two-way contingency table.
WARNING: 226 observations were deleted due to missing values.
ERROR: The table has too few valid active rows.
NOTE: SAS 系统由于错误而停止了该步的处理。
WARNING: 数据集 WORK.COOR 可能不完整。该步停止时,共有 0 个观测和 14 个变量。
NOTE: “PROCEDURE CORRESP”所用时间(总处理时间):
      实际时间         0.31 秒
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2009-7-25 00:02:05
不过你好像多发了,我删掉一个请别介意
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2009-7-25 09:42:29
爱萌 发表于 2009-7-25 00:02
不过你好像多发了,我删掉一个请别介意
是我这里网速不稳定,第一个发了一半的时候我把网页给关了,重新发的,没有想到这样也发上去了,呵呵。辛苦版主了
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