路过，看了的

1# janghee
回答如下：
data list free/a1,a2,a3,a4,a5,degree.
begin data.
5 5 5 5 5  2
1 5 5 5 5  3
5 5 5 5 5  3
1 1 1 5 5  3
5 5 5 5 5  3
1 5 5 5 5  1
end data.
*得到a1到a5中1和5的个数.
COUNT a.equal.1=a1 a2 a3 a4 a5(1).
COUNT a.equal.5=a1 a2 a3 a4 a5(5).
EXECUTE.
* 设定表格,得到总计交叉表.
CTABLES
  /VLABELS VARIABLES=a.equal.5 a.equal.1 degree DISPLAY=LABEL
  /TABLE a.equal.5 [SUM] + a.equal.1 [SUM] BY degree
  /CATEGORIES VARIABLES=degree ORDER=A KEY=VALUE EMPTY=EXCLUDE.