同求啊

我也希望知道，谢谢大侠指教啊!

arima(lh, order = c(1,0,1))
Call:
arima(x = lh, order = c(1, 0, 1))
Coefficients:
         ar1     ma1  intercept
      0.4522  0.1982     2.4101
s.e.  0.1769  0.1705     0.1358
sigma^2 estimated as 0.1923:  log likelihood = -28.76,  aic = 65.52
########
library(forecast)
Arima(lh, order = c(1,0,1))
Series: lh
ARIMA(1,0,1) with non-zero mean
Coefficients:
         ar1     ma1  intercept
      0.4522  0.1982     2.4101
s.e.  0.1769  0.1705     0.1358
sigma^2 estimated as 0.1923:  log likelihood=-28.76
AIC=65.52   AICc=66.45   BIC=73.01

谢谢啦 ，确实加了软件包之后就可以求了。
顺便问一下AICc又是什么东东呢

AICc考虑了有限样本的修正
AICc = AIC + 2k(k+1)/(n-k-1)
k是参数个数，n是样本大小