proc iml;

a=1;

b=a; or b=a[1,1];

more complicated case:

a={2,1,3};

b=a[2,1]; /* b=1*/

谢谢,又有一个要请教的:

a=1;

b是由九个a(值)生成的行向量,除了用b=a||a...,还有其他方法吗?

proc iml;
a=1;
b=repeat(a,9);
print b;

this is a column vector. Using transpose, you can obtain a row vector.

proc iml;
a=1;
b=repeat(a,9)`;
print b;

I uploaded a manul about IML functions. you can download it and find what you need.

[此贴子已经被作者于2007-5-23 5:02:44编辑过]