proc sql;
select max(price),year(day) as year from yourdsn
group by year;
quit;

楼主我爱你！

可以把price的值赋给一个数组
用数组来解决

define an ordered hash object by descending price and date

如果所有的计算都是针对同一支股票，365天包括当天的话，
data result;
        if _N_= 1 then do;
                declare hash h(dataset: "input", multidata: 'y');
                h.defineKey('stock_code');
                h.defineData('day', 'price');
                call missing(day, price);
                h.defineDone();
        end;

        set input(rename = (day = current_day price = current_price));
        max_price = 0;

        /* Iterate over the hash */
        rc = h.find(key: stock_code);
        do while (rc = 0);
                if (current_day - 365 < day <= current_day) then do;
                        max_price = max(max_price, price);
                end;
                rc = h.find_next(key: stock_code);
        end;
        keep stock_code current_day current_price max_price;
run;