hubifeng？ 发表于 2015-12-2 22:33
在R中输入?optimize，好好看看其用法和结果
maximum是指xlim的值
objective是函数的值，也就是你所求的值

The first evaluation of f is always at x_1 = a + (1-φ)(b-a) where (a,b) = (lower, upper) and phi = (sqrt(5) - 1)/2 = 0.61803.. is the golden section ratio. Almost always, the second evaluation is at x_2 = a + phi(b-a). Note that a local minimum inside [x_1,x_2] will be found as solution, even when f is constant in there, see the last example.

suimong 发表于 2015-12-4 02:57
上面这段出自optimize函数的帮助。所以是optimize函数的算法问题。