. rd lny lnx , mbw(50 100 200) gr z0(3.51) kernel(tri)
Two variables specified; treatment is
assumed to jump from zero to one at Z=3.51.

Assignment variable Z is lnx
Treatment variable X_T unspecified
Outcome variable y is lny

Command used for graph: lpoly; Kernel used: tri
Bandwidth: .1616547; loc Wald Estimate: -.4986326
Bandwidth: .08082735; loc Wald Estimate: -4.1496208
Bandwidth: .3233094; loc Wald Estimate: -.86327839
Estimating for bandwidth .1616546978190785
Estimating for bandwidth .0808273489095393
Estimating for bandwidth .323309395638157
------------------------------------------------------------------------------
         lny |      Coef.   Std. Err.      z    P>|z|     [95% Conf. Interval]
-------------+----------------------------------------------------------------
       lwald |  -.4986326   .2183702    -2.28   0.022    -.9266302    -.070635
     lwald50 |  -4.149621   .3199996   -12.97   0.000    -4.776809   -3.522433
    lwald200 |  -.8632784   .1600702    -5.39   0.000     -1.17701   -.5495466
------------------------------------------------------------------------------

结果中第一行是最优带宽（.1616547），第二行是0.5倍带宽（.08082735），第三行是2倍带宽（.3233094）。p值显示都很显著，拟合效果很好。

请问表格里的数字怎么解释啊

请问前辈这个怎么解释您会了吗？可否告知一下[抱拳]

同问结果的解释，就是数字的解释