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2006-03-10

两个问题: 我是初学者,谁能彻底解释DEGREES OF FREEDOM的含义?谢谢了

哪位大虾在帮我解释一下, ZERO CONDITIONAL MEAN的assumption 意义!MANY THANKS

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2006-3-10 11:30:00
你这么提问,人家谁还会回答阿~~
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2006-3-10 18:51:00

你这么提问,人家谁还会回答阿~~

DEGREES OF FREEDOM在论坛上搜一下呗

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2006-3-10 18:57:00
为我的提问方式感到歉意,我同样的问题已经提了好几次可是没有给予回答.给我感觉大家都在买卖东西. 我想人大的这个论坛存在在于学术探讨和帮助象我这样的"后进生". 苦于想知道答案所以才这么问的.望大家原谅
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2006-3-11 21:20:00

Let me try to give you some ideas.

Suppose you have Y(i)=b1+b2*X(i)+e(i), i=1,...,n (*1)

also denote x(i)=X(i)-X_bar, where X_bar is the sample mean of X(i), simialrly for y(i).

for ease of exposition, when thinking about degrees of freedom(hereafter, df), only look at Y(i), or y(i).

Now if you estimate the sample mean of Y(i), i.e., Y_bar, you lose one df. Why? take a simple example. suppose you have 4 numbers, But I tell you that the sample mean is (say) 5. I ask 4 students choose such 4 numbers such that the sample mean is 5. The students are free to choose any number, The 1st student is happy, the 2nd is happy, the 3rd is happy... now suppose the first three numbers chosen are 10, -2, 4, then the sum is 12. The 4th student is not happy because she must to choose 8 such that the average is 5 is satisfied. So we have 4 "observations", but in order to have the mean, we lose one df.

Note that this is some sort of constraints (i.e. to calculate the sample mean).

I also note that estimate parameters in the mdoel can also be viewed constraints.

When you estimate one parameter, e.g. b1 in (*1), you impose one constraint upon the system.

[此贴子已经被作者于2006-3-12 3:25:29编辑过]

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2006-3-11 21:28:00

Now instead of (*1), we work with deviations y(i) and x(i), the new model of interest becomes

y(i)=b2*x(i)+u(i), i=1,...,n-1 (*2)

where the No. of Obs. isnow n-1, because when I take the mean, I lose one observations or, one df.

in order to have b2_hat, we also need to impose one constraint over the systems. what's that.

In view of OLS, we need the sum of residuals to be zero. this can be attacked thus: in x-y plane, there is a line with posi. slope, n-1 points is scattered around this fitted line. suppose n-1=10. then loosely speaking, then first 9 point is somhow free, but the last one can only be somewhere which has been determined by other 9 points such that the sum of residuals is zero. like the exmple for mean given in Floor 5 (F5).

So the idea is that estiamting b2 can also be thought of imposing one constraint over th system/model.

SImilarly, for b3, b4, if you have.

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