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在用frontier4.1中的BC1995模型(模型2)计算面板数据时,结果如何解释?
Output from the program FRONTIER (Version 4.1c)
instruction file = kcsjm2.ins
data file = kcsjm2.dta
Tech. Eff. Effects Frontier (see B&C 1993)
The model is a production function
The dependent variable is not logged
the ols estimates are :
coefficient standard-error t-ratio
beta 0 0.22591901E+05 0.35217695E+05 0.64149290E+00
beta 1 0.11619231E+01 0.10569134E+01 0.10993551E+01
beta 2 0.11558298E+01 0.17379257E-01 0.66506281E+02
beta 3 0.66236876E-01 0.83244913E-01 0.79568677E+00
sigma-squared 0.73858757E+11
log likelihood function = -0.25892648E+04
the estimates after the grid search were :
beta 0 0.28286612E+06
beta 1 0.11619231E+01
beta 2 0.11558298E+01
beta 3 0.66236876E-01
delta 1 0.00000000E+00
sigma-squared 0.14001307E+12
gamma 0.76000000E+00
iteration = 0 func evals = 20 llf = -0.25768253E+04
0.28286612E+06 0.11619231E+01 0.11558298E+01 0.66236876E-01 0.00000000E+00
0.14001307E+12 0.76000000E+00
gradient step
iteration = 5 func evals = 44 llf = -0.25652833E+04
0.28286612E+06-0.58721959E+00 0.12076266E+01 0.44433034E-01 0.11275841E+01
0.14001307E+12 0.87829753E+00
iteration = 10 func evals = 142 llf = -0.25633269E+04
0.28286612E+06-0.19481303E+01 0.12412228E+01 0.97222537E-01 0.21621906E+01
0.14001307E+12 0.91439169E+00
search failed. fn val indep of search direction
iteration = 11 func evals = 144 llf = -0.25633269E+04
0.28286612E+06-0.19481303E+01 0.12412228E+01 0.97222537E-01 0.21621906E+01
0.14001307E+12 0.91439169E+00
the final mle estimates are :
coefficient standard-error t-ratio
beta 0 0.28286612E+06 0.10002412E+01 0.28279791E+06
beta 1 -0.19481303E+01 0.96951344E+00 -0.20093897E+01
beta 2 0.12412228E+01 0.20635989E-01 0.60148451E+02
beta 3 0.97222537E-01 0.79695107E-01 0.12199311E+01
delta 1 0.21621906E+01 0.56144440E+00 0.38511214E+01
sigma-squared 0.14001307E+12 0.10000000E+01 0.14001307E+12
gamma 0.91439169E+00 0.24391378E-01 0.37488316E+02
log likelihood function = -0.25633269E+04
LR test of the one-sided error = 0.51875829E+02
with number of restrictions = 2
[note that this statistic has a mixed chi-square distribution]
number of iterations = 11
(maximum number of iterations set at : 100)
number of cross-sections = 31
number of time periods = 6
total number of observations = 186
thus there are: 0 obsns not in the panel
covariance matrix :
0.10004824E+01 0.12047308E-01 -0.90968524E-04 -0.52830483E-03 -0.29906358E-02
-0.34834248E-15 0.26294225E-03
0.12047308E-01 0.93995632E+00 -0.13992620E-01 -0.36154807E-01 -0.33354104E+00
0.78740787E-11 -0.96356508E-02
-0.90968524E-04 -0.13992620E-01 0.42584405E-03 -0.27071362E-03 0.78051863E-02
-0.46455443E-13 0.27786369E-03
-0.52830483E-03 -0.36154807E-01 -0.27071362E-03 0.63513100E-02 0.14603726E-01
0.49512128E-12 0.16656540E-03
-0.29906358E-02 -0.33354104E+00 0.78051863E-02 0.14603726E-01 0.31521981E+00
0.51806195E-12 0.68671596E-02
-0.34834248E-15 0.78740787E-11 -0.46455443E-13 0.49512128E-12 0.51806195E-12
0.10000000E+01 0.73861353E-12
0.26294225E-03 -0.96356508E-02 0.27786369E-03 0.16656540E-03 0.68671596E-02
0.73861353E-12 0.59493932E-03