open data 12345_plas.xls
data(format=xls,org=columns) 1 1990 EX PLAS
set lex = log(ex)
set lplas = log(plas)
set dlex = lex-lex{1}
set dlplas = lplas-lplas{1}
*Use @JohMLE to test the cointegrating rank
*RC restricts aconstant to the CV.
@johmle(lags=2,det=rc,cv=cvector)
# lex lplas
此处的滞后阶数又应该用@varlagselect(lags=6,crit=bic) (#lex lplas 还是 #dex dplas)所得到的滞后阶数呢?
*Setting the Cointegrating Vectors
set ect = lex+(-4.664164/-32.943952)*lplas+(138.156062/-32.943952)
system(model=ectmodel)
variables dlex dlplas
lags 1 to 2
det ect{1}
end(system)
estimate
此处的滞后数等于varlagselect中取得的滞后数,而这里也是对对数收益的滞后,那么第一步滞后选择理应是对对数收益滞后的选择啊???