<p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt;"><span style="; FONT-FAMILY: 宋体;">短期生产函数<span lang="EN-US">X=x</span>（<span lang="EN-US">L</span>）<span lang="EN-US"><br/>     <p></p></span></span></p><p></p><p></p><p></p><p></p><p></p><p></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt;"><span lang="EN-US" style="; FONT-FAMILY: 宋体;">X</span><span style="; FONT-FAMILY: 宋体;">＇<span lang="EN-US">>0,X</span>＂<span lang="EN-US"><0 ,q</span>为正常生产的概率，（<span lang="EN-US">1-q</span>）为停产的概率<span lang="EN-US"><br/>     <p></p></span></span></p><p></p><p></p><p></p><p></p><p></p><p></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt;"><span style="; FONT-FAMILY: 宋体;">利润π<span lang="EN-US">=q*[p*x(L)-wL-a]+(1-q)[-wL-a]=q*</span>π<sub><span lang="EN-US">1</span></sub><span lang="EN-US">+(1-q)*</span>π<sub><span lang="EN-US">2</span></sub><span lang="EN-US"><br/>     <p></p></span></span></p><p></p><p></p><p></p><p></p><p></p><p></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt;"><span lang="EN-US" style="; FONT-FAMILY: 宋体;">VNM</span><span style="; FONT-FAMILY: 宋体;">函数为<span lang="EN-US"><br/>     <p></p></span></span></p><p></p><p></p><p></p><p></p><p></p><p></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt;"><span lang="EN-US" style="; FONT-FAMILY: 宋体;">U</span><span style="; FONT-FAMILY: 宋体;">（π）<span lang="EN-US">=q*U(</span>π<sub><span lang="EN-US">1</span></sub><span lang="EN-US">)+(1-q)*U(</span>π<sub><span lang="EN-US">2</span></sub><span lang="EN-US">) <p></p></span></span></p><p></p><p></p><p></p><p></p><p></p><p></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt;"><span lang="EN-US" style="; FONT-FAMILY: 宋体;">maxU(</span><span style="; FONT-FAMILY: 宋体;">π<span lang="EN-US">) </span>一阶条件为：<span lang="EN-US"><br/>     <p></p></span></span></p><p></p><p></p><p></p><p></p><p></p><p></p><p class="MsoNormal" style="MARGIN: 0cm 0cm 0pt;"><span lang="EN-US" style="; FONT-FAMILY: 宋体;">qU</span><span style="; FONT-FAMILY: 宋体;">＇<span lang="EN-US">(</span>π<sub><span lang="EN-US">1</span></sub><span lang="EN-US">)[px</span>＇<span lang="EN-US">(L)-w]+(1-q)U</span>＇<span lang="EN-US">(</span>π<sub><span lang="EN-US">2</span></sub><span lang="EN-US">)[-w]=0 <p></p></span></span></p><p></p><p></p><p></p><p></p><p></p><p></p><p>求解： </p><p>  <br/></p>

[此贴子已经被作者于2007-12-4 21:29:52编辑过]