水平:
Null Hypothesis: LNB has a unit root
Exogenous: None
Lag Length: 1 (Automatic - based on SIC, maxlag=4)
t-Statistic Prob.*
Augmented Dickey-Fuller test statistic 1.385579 0.9532
Test critical values: 1% level -2.679735
5% level -1.958088
10% level -1.607830
一阶:
Null Hypothesis: D(LNB) has a unit root
Exogenous: Constant
Lag Length: 0 (Automatic - based on SIC, maxlag=4)
t-Statistic Prob.*
Augmented Dickey-Fuller test statistic -2.179495 0.2187
Test critical values: 1% level -3.788030
5% level -3.012363
10% level -2.646119
二阶:
Null Hypothesis: D(LNB,2) has a unit root
Exogenous: Constant, Linear Trend
Lag Length: 0 (Automatic - based on SIC, maxlag=4)
t-Statistic Prob.*
Augmented Dickey-Fuller test statistic -3.249349 0.1034
Test critical values: 1% level -4.498307
5% level -3.658446
10% level -3.268973
还有在ADF检验的时候,我是用下面的办法做的,这样对吗?
【一般进行ADF检验要分3步:
1 对原始时间序列进行检验,此时第二项选level,第三项选None.如果没通过检验,说明原始时间序列不平稳;
2 对原始时间序列进行一阶差分后再检验,即第二项选1st difference,第三项选intercept,若仍然未通过检验,则需要进行二次差分变换;
3 二次差分序列的检验,即第二项选择2nd difference ,第四项选择Trend and intercept.一般到此时间序列就平稳了!】